How to convert this very simple .htaccess to nginx?

Sandro Benevides asked:

I’m using this .htaccess that pass everything after url to $param, so goes to php as $_GET[‘param’]=news/id. But nginx is always throwing me to 404 page.

My htaccess:

RewriteEngine On
RewriteCond %{SCRIPT_FILENAME} !-f
RewriteCond %{SCRIPT_FILENAME} !-d
RewriteRule  (.*) index.php?param=$1

What I tried in nginx default.conf:

server {
        listen 80;
        listen [::]:80;
        root    /var/www/html;

        location / {
                if (!-f $uri){
                        set $rule_0 1$rule_0;
                if (!-d $uri){
                        set $rule_0 2$rule_0;
                if ($rule_0 = "21"){
                rewrite ^(.*) index.php?param=$1;

My answer:

You don’t use if here at all, nor do you manually check for the existence of files. This common pattern is handled instead by try_files.

For example:

location / {
    try_files $uri $uri/ /index.php?param=$uri;

(If your web app is broken and can’t handle the leading / in the URI, fix the web app if possible, or see this question if not.)

View the full question and any other answers on Server Fault.

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